Foundation June 2017 Paper 2 Q11
11 Solve \(\qquad 4x - 3 = 14\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(4x = 14 + 3\) or \(4x = 17\) or \((14 + 3) \div 4\) or \(17 \div 4\) or \(x - \dfrac{3}{4} = \dfrac{14}{4}\) | M1 | |
| 4.25 or \(\dfrac{17}{4}\) or \(4\dfrac{1}{4}\) | A1 |
Additional guidance
| Embedded answer of 4.25 with 4.25 not selected on answer line eg \(4 \times 4.25 - 3 = 14\) with no answer given or answer of 14 or 17 | M1A0 |
| \(14 + 3\) and answer 4.25 | M1A1 |
| \(14 + 3\) only | M0A0 |
| Trial and improvement with answer 4.25 | M1A1 |
| Trial and improvement with no answer or answer other than 4.25 | M0A0 |
| 4.25 or \(\dfrac{17}{4}\) or \(4\dfrac{1}{4}\) seen and then answer 4 given | M1A1 |
| Answer of \(\times 4.25\) | M1A0 |
| \(17 \div 4\) (and no further) | M1A0 |