Foundation June 2017 Paper 1 Q26
26 Write 36 as a product of prime factors.
Give your answer in index form. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Any correct product of 36 using a prime factor | M1 | 2 and 18 2 and 2 and 9 3 and 12 3 and 3 and 4 2 and 3 and 6 May be on a factor tree or repeated division |
| 2 and 2 and 3 and 3 | A1 | oe May be on a factor tree or repeated division |
| \(2^2 \times 3^2\) or \(3^2 \times 2^2\) | A1 |
Additional guidance
| Allow any number of 1s included as factors for up to M1A1 only | |
| \(1 \times 2^2 \times 3^2\) | M1A1A0 |
| \(2^2 .\, 3^2\) | M1A1A1 |
| \(2 + 2 + 3 + 3\) | M1A1A0 |
| \(2^2 + 3^2\) | M1A1A0 |
| \(2^2 3^2\) or \(2^2,\ 3^2\) | M1A1A0 |
| \(2 \times 2 \times 3 \times 3\) and \(2^2 \times 3^2\) on answer line but \(2 \times 2 \times 3 \times 3 = 2^2 \times 3^2\) on answer line | M1A1A0 M1A1A1 |
| \(2^2 \times 3^2 = 6^4\) | M1A1A0 |
| \(6 \times 6\) with no prime factorisation | M0A0A0 |