Higher June 2025 Paper 1R Q10
10 The diagram shows two water containers.
One is a cuboid and one is a cylinder.

Diagram NOT accurately drawn
The cuboid measures 35 cm by 28 cm by 20 cm
The surface of the water in the cuboid is 9 cm above the base of the cuboid.
The cylinder has a radius of 10 cm and a height of 33 cm
The cylinder is completely full of water.
Izzy is going to pour all the water from the cylinder into the cuboid.
Show that the cuboid will not be completely full of water.
(3)
| Scheme | Marks |
|---|---|
| (volume of water =) \(9 \times 35 \times 28 (= 8820)\) or (total volume of cuboid =) \(20 \times 35 \times 28 (= 19600)\) or (volume of space =) \((20 - 9) \times 35 \times 28 (= 10780)\) | M1 |
| \(\pi \times 10^2 \times 33\) (= \(3300\pi\) or 10367(.25...)) oe | M1 |
| (total volume of water =) “8820” + “10367(.25...)” (= 19187(.25...)) (difference between volumes of both solids =) “19600” − “10367(.25…)”(= 9232(.74…)) (volume not filled =) “19600” – “8820” – “10367(.25…)” (=412(.74…)) Working required Answer: Shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for a method to find a relevant volume for the cuboid
M1: (indep) for a method to find the volume of the cylinder, accept a volume in the range 10362 to 10368.6
Allow 3.14… or \(\dfrac{22}{7}\) for \(\pi\)
A1: correct workings with accurate figures
eg
| Value 1 | Value 2 |
|---|---|
| 10780 | 10367(.25…) accept 10362 to 10372 |
| 19600 | 19187(.25…) accept 19182 to 19192 |
| 8820 | 9232(.74…) accept 9228 to 9238 |
| 412(.74…) or 413 accept 408 to 418 | none needed |