Higher June 2025 Paper 3 Q12
12 The price of a holiday is increased by 10%
After the increase, the price of the holiday is £440
Jim says,
“10% of £440 is £44 so the price of the holiday before the increase was £396”
(a) Is Jim correct?
Explain your answer. (1)
Explain your answer. (1)
Tina sells bikes.
In November, Tina sold 25% fewer bikes than she sold in October.
In December, Tina sold 50% more bikes than she sold in November.
In December, Tina sold 180 bikes.
(b) How many bikes did Tina sell in October? (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| No with reason | C1 | No with reason Acceptable examples It’s 10% of the original price, not 10% of 440 He found the percentage of the new amount not the original amount He found 10% of the increased value The original price is £400 100% is £400 / 100% is not £440 / 110% is £440 10% is £40 / 10% is not £44 / 11% is £44 99% is 396 10% of 396 is 39.6(0) 110% of 396 is 435.6(0) He should have divided by 1.1 Not acceptable examples No, 440 minus 10% is not 396 100% is not £396 £440 is the price after the increase / The original price is not £440 He has to find 90% of 440 He has to find 110% of 440 It should be £484 Jim is correct / Yes …… |
| Answer | Mark | Mark scheme |
|---|---|---|
| 160 | P1 | for process to find the number sold in November, eg \(180 \div 150 \times 100\) or \(180 \div 1.5\ (= 120)\) oe or for \(0.75 \times 1.5\ (= 1.125)\) oe or for \(75 \times 1.5\ (= 112.5)\) oe |
| P1 | for a process to find the number sold in October, eg \(\text{``}120\text{''} \div 75 \times 100\) oe eg \(\text{``}120\text{''} \div 0.75\) or \(180 \div \text{``}1.125\text{''}\) oe eg \(180 \div \text{``}112.5\text{''} \times 100\) or \([\text{value}] \div 0.75\) oe | |
| A1 | cao |
Additional guidance
[value] can be any value they believe to be the number of bikes sold in November or 180