Higher June 2025 Paper 2 Q10
10 Solve \(\dfrac{14 - x}{3} = 3x\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 1.4 | M1 | for a correct first step eg \(\dfrac{14 - x}{3} \times 3 = 3x \times 3\) or \(\dfrac{14}{3} - \dfrac{1}{3}x + \dfrac{1}{3}x = 3x + \dfrac{1}{3}x\) oe |
| A1 | oe, eg \(\dfrac{14}{10}\) |
Additional guidance
For M mark, step must be carried out not just intention shown.
For example if you see \[\begin{array}{ccc} \dfrac{14 - x}{3} &=& 3x \\ \times 3 && \times 3 \end{array}\] Only award M1 when you see \(14 - x = kx\) where \(k \gt 3\)