A2 June 2023 Paper 1 Q7
7 The diagram below shows the curve with polar equation \(r = a(1 - 2\sin\theta)\) for \(0 \leqslant \theta \leqslant 2\pi\), where \(a\) is a positive constant.

The curve crosses the initial line at A, and the points B and C are the lowest points on the two loops.
(a) Find the values of \(r\) and \(\theta\) at the points A, B and C. [3]
(b) Find the set of values of \(\theta\) for the points on the inner loop (shown in the diagram with a broken line). [3]
| Scheme | Marks | AO |
|---|---|---|
| A: \(r = a,\ \theta = 0\) | B1 | 1.1 |
| B: \(r = -a,\ \theta = \pi/2\) | B1 | 1.1 |
| C: \(r = 3a,\ \theta = 3\pi/2\) | B1 | 1.1 |
| [3] |
Notes
B1: (A) or \(\theta = 2\pi\)
| Scheme | Marks | AO |
|---|---|---|
| \(\sin\theta \gt \dfrac{1}{2}\) | M1 | 3.1a |
| \(\dfrac{1}{6}\pi, \dfrac{5}{6}\pi\) | A1 | 1.1 |
| \(\dfrac{1}{6}\pi \lt \theta \lt \dfrac{5}{6}\pi\) | A1 | 1.1 |
| [3] |
Notes
M1: Allow \(\sin\theta = \frac{1}{2}\) (or \(\lt \frac{1}{2}\) or \(\leqslant \frac{1}{2}\) or \(\geqslant \frac{1}{2}\))
A1: both
A1: condone \(\leqslant\) for \(\lt\)