A2 June 2022 Paper 1 Q4
4 The vector \(\mathbf{v}\) is an eigenvector of the matrix \(\mathbf{N}\) with corresponding eigenvalue 4
The vector \(\mathbf{v}\) is also an eigenvector of the matrix \(\mathbf{M}\) with corresponding eigenvalue 3
Given that
\[\mathbf{NM}^2\mathbf{v} = \lambda\mathbf{v}\]find the value of \(\lambda\)
Circle your answer. [1 mark]
- 10
- 24
- 36
- 144
| Scheme | Marks | AO |
|---|---|---|
| Circles correct answer | B1 | 2.2a |
| (1 mark) |
Typical solution
36