AS June 2025 Paper 1 Q2
2.
In this question you must show all stages of your working.
Solutions relying entirely on calculator technology are not acceptable.
\[\mathrm{f}(z) = 4z^3 - 12z^2 - 95z + 325\]Given that \(\mathrm{f}(-5) = 0\)
| Scheme | Marks | AO |
|---|---|---|
| States or uses \((z + 5)\) factor | B1 | 1.2 |
| \((z + 5)\left(4z^2 - \ldots\right)\) | M1 | 1.1b |
| \((z + 5)\left(4z^2 - 32z + 65\right)\) | A1 | 1.1b |
| (3) |
Notes
B1: Recalls the fact that if \(\mathrm{f}(-5) = 0\) then \((z + 5)\) is a factor
M1: Finds the quadratic factor with a \(4z^2\) term, any method. Condone using a factor of \((z - 5)\)
A1: Correct factorised expression for \(\mathrm{f}(z)\)
| Scheme | Marks | AO |
|---|---|---|
| \(z = \dfrac{-(-32) \pm \sqrt{(-32)^2 - 4(4)(65)}}{2(4)} = \ldots\) Completing the square \(4(z \pm 4)^2 + q = 0 \Rightarrow z = \ldots\) where \(q \gt 0\) | M1 | 1.1b |
| \(z = \left\{\dfrac{32 \pm \sqrt{-16}}{8} = \right\}\dfrac{32 \pm 4\mathrm{i}}{8} = \dfrac{8 \pm \mathrm{i}}{2}\) * | A1* | 2.1 |
| (2) |
Notes
M1: Uses a correct method to show where the complex roots have come from.
Note just uses the calculator is M0
A1: Completes the method to show the complex roots. There needs to be an intermediate line of work with either 4i or \(4\sqrt{-1}\) term
Note: \(z = \dfrac{32 \pm \sqrt{-16}}{8} = \dfrac{8 \pm \mathrm{i}}{2}\) is M1 A0
Alternative
| Scheme | Marks | AO |
|---|---|---|
| Uses the roots to find the equation \(\left(z - \dfrac{8 + \mathrm{i}}{2}\right)\left(z - \dfrac{8 - \mathrm{i}}{2}\right) = z^2 - 8z + \dfrac{65}{4} = 0\) This could come from using the sum and product of roots | M1 | 1.1b |
| \(4z^2 - 32z + 65 = 0\) therefore roots are \(\dfrac{8 \pm \mathrm{i}}{2}\) | A1* | 2.1 |
| (2) |
(Corrected from the printed mark scheme: the alternative prints \(z^2 - 8z + \dfrac{64}{4} = 0\); the product of the roots is \(\dfrac{65}{4}\).)
M1: uses the roots and expands
A1: Achieves the correct equation with = 0 no errors and a conclusion
| Scheme | Marks | AO |
|---|---|---|
| \(-2,\ \dfrac{10 \pm \mathrm{i}}{4}\) or \(-2,\ \dfrac{5}{2} \pm \dfrac{\mathrm{i}}{4}\) or \(-2,\ 2.5 \pm 0.25\mathrm{i}\) | B1 B1 | 2.2a 2.2a |
| (2) | ||
| (7 marks) |
Notes
B1: Deduces one correct root
B1: Deduces all 3 correct roots