AS June 2025 Q4
4. A 5-question test is taken by 80 students.
Each question was answered either correctly or incorrectly.
| Number of questions answered correctly | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| Observed frequency | 15 | 23 | 31 | 9 | 2 | 0 |
Anisa believes that the number of questions answered correctly can be modelled using a binomial distribution.
In order to test her belief, Anisa first calculates some of the expected frequencies.
| Number of questions answered correctly | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| Expected frequency | 13.45 | \(r\) | \(s\) | 10.58 | 2.27 | 0.19 |
| Scheme | Marks | AO |
|---|---|---|
| \(\text{mean} = \dfrac{[15 \times 0 +]\, 23 \times 1 + 31 \times 2 + 9 \times 3 + 4 \times 2\, [+ 5 \times 0]}{80}\ [= 1.5]\) | M1 | 1.1b |
| \(p = \dfrac{1.5}{5} = 0.3\)* | A1* | 1.1b |
| (2) |
Notes
M1: Attempt to find the mean with at least 3 correct products
A1*: cso fully correct solution leading to given answer 0.3
May be done in a single calculation for M1A1
\(\dfrac{[15 \times 0 +]\, 23 \times 1 + 31 \times 2 + 9 \times 3 + 4 \times 2\, [+ 5 \times 0]}{400} = 0.3\)
| Scheme | Marks | AO |
|---|---|---|
| [\(X \sim \mathrm{B}(5, 0.3)\)] \(\mathrm{P}(X = 1) = 0.36015\) or \(\mathrm{P}(X = 2) = 0.3087\) | M1 | 1.1b |
| \(r = 80 \times 0.36015 = 28.8\ldots\) awrt 28.8 | A1 | 1.1b |
| \(s = 80 \times 0.3087 = 24.69\ldots\) awrt 24.7 | A1 | 1.1b |
| (3) |
Notes
M1: Either correct probability awrt 0.36 or awrt 0.31
(may be implied by a correct value of \(r\) or a correct value of \(s\))
A1: awrt 28.8
A1: awrt 24.7
| Scheme | Marks | AO |
|---|---|---|
| Need to combine last 3 columns since \(E_i\) are \(\lt 5\) | B1 | 2.4 |
| Therefore 4 – 2 degrees of freedom since proportion for Binomial estimated from \(O_i\) | B1 | 2.4 |
| (2) | ||
| (7 marks) |
Notes
B1: For explaining need to pool last 3 columns/cells and \(E_i \lt 5\)
allow 4 cells remaining after pooling for need to pool last 3 columns/cells
must be referencing expected frequencies (not observed frequencies)
B1: For proportion/parameter/\(p\)/mean/0.3 calculated/estimated (from data/\(O_i\))
and 2 constraints or 4 – 2 or 4 – 1 – 1 which must come from correct reasoning