Higher June 2018 Unit 2 Q10
10. Factorise \(4m^2 - 289\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| \((2m + 17)(2m - 17)\) | B2 | B1 for \((2m \ldots 17)(2m \ldots 17)\) OR B1 for \((2m + \sqrt{289})(2m - \sqrt{289})\) OR \(4(m + 8.5)(m - 8.5)\) OR \((4m + 34)(m - 8.5)\) OR \((4m - 34)(m + 8.5)\). Mark final answer. Penalise -1 further work, e.g. solving an equation. |