Higher June 2022 Paper 5 Q11
11 \(y\) is inversely proportional to \(x^2\).
\(y = 9\) when \(x = 2\).
Find the value of \(y\) when \(x = 10\). [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 0.36 oe final answer | 3 | B1 for \(y = \frac{k}{x^2}\) oe soi by \(9 = \frac{k}{2^2}\) or \(k = 36\) M1 for \(y = \frac{\textit{their } k}{10^2}\) OR M2 for \(2^2 \times 9 = 10^2 \times y\) oe | oe e.g. for 3 marks \(\frac{36}{100}\) oe |