Foundation November 2018 Paper 1 Q8
8 Here is a function.
The input is \(x\) and the output is \(y\).
Write an algebraic expression for \(y\) in terms \(x\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [\(y =\)] \(\dfrac{x}{3} + 9\) or [\(y =\)] \(x \div 3 + 9\) final answer | 2 | M1 for [\(y =\)] \(\dfrac{x}{3} + k\) or [\(y =\)] \(jx + 9\) | \(j \ne 0\) |