Higher June 2019 Paper 1 Q7
7.
\[\mathbf{p} = \begin{pmatrix}4\\2\end{pmatrix} \ \text{and}\ \ \mathbf{q} = \begin{pmatrix}-3\\2\end{pmatrix}\]Work out the column vector \(\dfrac{1}{2}\mathbf{p} - \mathbf{q}\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| \(\begin{pmatrix}5\\-1\end{pmatrix}\) | B2 | Mark final answer for B2 B1 for each element or for (½\(\mathbf{p}\) =) \(\begin{pmatrix}2\\1\end{pmatrix}\) oe seen or for \(\left(\dfrac{5}{-1}\right)\) or for \(\begin{matrix}5\\-1\end{matrix}\) in working space without brackets; allow \(\begin{matrix}2\\1\end{matrix}\) seen for B1. |
| (2) |