M3 January 2005 Q4
4.

In a game at a fair, a small target \(C\) moves horizontally with simple harmonic motion between the points \(A\) and \(B\), where \(AB = 4L\). The target moves inside a box and takes 3 s to travel from \(A\) to \(B\). A player has to shoot at \(C\), but \(C\) is only visible to the player when it passes a window \(PQ\), where \(PQ = b\). The window is initially placed with \(Q\) at the point as shown in Figure 4. The target \(C\) takes 0.75 s to pass from \(Q\) to \(P\).
(a) Show that \(b = (2 - \sqrt{2})L\). (5)
(b) Find the speed of \(C\) as it passes \(P\). (2)

For advanced players, the window \(PQ\) is moved to the centre of \(AB\) so that \(AP = QB\), as shown in Figure 5.
(c) Find the time, in seconds to 2 decimal places, taken for \(C\) to pass from \(Q\) to \(P\) in this new position. (3)
| Scheme | Marks |
|---|---|
| \(6 = \dfrac{2\pi}{\omega} \Rightarrow \omega = \dfrac{\pi}{3}\) | M1 |
| \(a = 2L\) | B1 |
| \(x = 2L\cos\omega t\) | M1 |
| \(2L - b = 2L\cos\left(\dfrac{\pi}{3} \cdot \dfrac{3}{4}\right)\) | A1ft |
| \(b = L(2 - \sqrt{2})\) * | A1 cso |
| (5) |
| Scheme | Marks |
|---|---|
| \(\dot{x} = -2L\omega\sin\omega t\) | |
| \(= -2L\dfrac{\pi}{3}\sin\dfrac{\pi}{4}\) | M1 |
| Speed \(= \dfrac{\sqrt{2}L\pi}{3}\) | A1 |
| (2) |
| Scheme | Marks |
|---|---|
| \(\tfrac{1}{2}(2-\sqrt{2})L = 2L\sin\omega t\) | M1 A1 |
| \(t = 0.1469\ldots\) | |
| \(\therefore\) Total time \(= 2 \times 0.14\ldots\) | |
| \(= 0.28\) (2 d.p.) | A1 |
| (3) | |
| (10 marks) |