4400 Higher November 2010 Paper 3 Q6
6
(a) Solve \(7x + 3 = 2x - 4\) (3)
(b) Solve \(\dfrac{16 - 5y}{3} = 2\) (3)
| Scheme | Marks |
|---|---|
| \(7x - 2x = -4 - 3\) | M1 |
| \(5x = -7\) | M1 |
| −1.4 | A1 |
| (3) |
Notes
M1: correct gathering of terms
A1: Accept \(-\frac{7}{5}\) (not \(-7 \div 5\)) No working: M0A0
| Scheme | Marks |
|---|---|
| \(16 - 5y = 2 \times 3\) | M1 |
| \(-5y = -10\) oe | M1 |
| 2 | A1 |
| (3) | |
| (6 marks) |
Notes
M1: \(\frac{16}{3} - 2 = \frac{5y}{3}\)
M1: \(\frac{10}{3} = \frac{5y}{3}\)
A1: Accept \(\frac{-10}{-5}\) (not \(-10 \div -5\)) No working: M0A0