4400 Higher November 2010 Paper 3 Q14
14 The diagram shows the graph of \(y = x^2 - 4x + 3\) for \(-1 \leqslant x \leqslant 5\)
(a) Use the graph to solve the equation \(x^2 - 4x + 3 = 2\) (2)
(b) By drawing a suitable straight line on the diagram, solve the equation \(x^2 - 4x + 3 = x + 1\) (3)
| Scheme | Marks |
|---|---|
| 0.2 to 0.3, 3.7 to 3.8 | B2 |
| (2) |
Notes
B2: inclusive; B1 for each
| Scheme | Marks |
|---|---|
| Draw \(y = x + 1\) | M1 |
| 0.4 to 0.5 & | A1 |
| 4.5 to 4.6 | A1 |
| (3) | |
| (5 marks) |
Notes
M1: for \(0 \leqslant x \leqslant 5\)
A1: inclusive dep on M1
A1: inclusive dep on M1