4400 Higher November 2005 Paper 4 Q21

EdexcelHigherOld spec4 marksAdvanced Trigonometry Pythagoras

21 The diagram shows a pyramid.
The base, \(ABCD\), is a horizontal square of side 10 cm.
The vertex, \(V\), is vertically above the midpoint, \(M\), of the base.
\(VM = 12\) cm.

Square-based pyramid VABCD with base side 10 cm, M the centre of the base and VM vertical

Diagram NOT accurately drawn

Calculate the size of angle \(VAM\).

(4)

Scheme	Marks
\(5^2 + 5^2\) or \(10^2 + 10^2\)	M1
\(\sqrt{50}\) or \(\frac{1}{2}\sqrt{200}\) or 7.07(…)	M1
\(\tan VAM = 12\) / (her 7.07) oe	M1
59.49(…) or 59.5	A1
	(4)
	(4 marks)

Notes