4MA0 Higher June 2016 Paper 3 Q6
6
(a) Show that \(\dfrac{3}{10} + \dfrac{2}{15} = \dfrac{13}{30}\) (2)
(b) Show that \(2\dfrac{5}{8} \div 1\dfrac{1}{6} = 2\dfrac{1}{4}\) (3)
| Scheme | Marks |
|---|---|
| \(\dfrac{9}{30} + \dfrac{4}{30}\) | M1 |
| shown | A1 |
| (2) |
Notes
M1: for \(\dfrac{9}{30}\) or \(\dfrac{4}{30}\) or
both fractions expressed as equivalent fractions with denominators that are a common multiple of 10 and 15 eg. \(\dfrac{45}{150}\) and \(\dfrac{20}{150}\)
A1: conclusion to given answer coming from correct working
| Scheme | Marks |
|---|---|
\(\dfrac{21}{8} \div \dfrac{7}{6}\) or \(\dfrac{21}{8}\) and \(\dfrac{7}{6}\) | M1 |
| \(\dfrac{21}{8} \times \dfrac{6}{7}\) or \(\dfrac{126}{56}\) | M1 |
| shown | A1 |
| (3) |
Notes
M1: Both fractions expressed as improper fractions eg. \(\dfrac{63}{24}, \dfrac{28}{24}\)
M1: or for both fractions expressed as equivalent fractions with denominators that are a common multiple of 8 and 6 eg. \(\dfrac{126}{48} \div \dfrac{56}{48}\) or \(\dfrac{63}{24} \div \dfrac{28}{24}\)
A1: conclusion to \(2\dfrac{1}{4}\) or \(\dfrac{9}{4}\) from correct working – either sight of the result of the multiplication e.g. \(\dfrac{126}{56}\) must be seen or correct cancelling prior to the multiplication with \(\dfrac{9}{4}\)