4MA0 Higher June 2011 Paper 4 Q10
10 Express 126 as a product of its prime factors.
(3)
| Scheme | Marks |
|---|---|
| 3 or more correct factors of which 2 are from 2,3,3,7 | M1 |
| All 4 correct prime factors & no extras (ignore 1’s) Answer: 2, 3, 3, 7 or 2, 3, 3, 7, 1 or 2×3×3×7×1 | M1 |
| 2 × 3 × 3 × 7 | A1 |
| (Total 3 marks) |
Notes
M1: e.g 2 × 3 × 21 or 2, 3, 21 must multiply to 126
could be implied from a factor tree or division ladder
M1: could be implied from a factor tree or division ladder
A1: any order, do not accept inclusion of 1’s
must be a product on answer line (dots or crosses)
Apart from questions 5b, 8, 15d, 20b, 21b, 23, 24b (where the mark scheme states otherwise) the correct answer, unless clearly obtained by an incorrect method, should be taken to imply correct working.