4MA0 Higher June 2011 Paper 3 Q7
7 The perimeter of a triangle is 90 cm.
The lengths of the sides of the triangle are in the ratios 3 : 5 : 7
Work out the length of the longest side of the triangle.
(3)
| Scheme | Marks |
|---|---|
| 3+5+7 or 15 | M1 |
| 90 ÷ (3+5+7) or 90 ÷ “15” or 6 or \(\frac{7}{15}\) oe | M1 |
| 42 | A1 |
| (Total 3 marks) |
Notes
M1: 15 may be denominator of fraction or coefficient in an equation such as \(15x = 90\)
M1: dep
A1: Also award for 18 : 30 : 42