4400 Higher June 2010 Paper 4 Q9
9 The depth of water in a reservoir increases from 14 m to 15.75 m.
Work out the percentage increase.
(3)
| Scheme | Marks |
|---|---|
15.75 − 14 (= 1.75) or \(\dfrac{15.75}{14} \times 100\) (= 112.5) | M1 |
\(\dfrac{\text{“}1.75\text{”}}{14} \times 100\) or “112.5” − 100 | M1dep |
| 12.5 | A1 |
| (3) | |
| (3 marks) |
Notes
M1dep: allow \(\dfrac{\text{“}1.75\text{”}}{15.75} \times 100\) (= 11.1)
A1: cao
14/15.75 × 100 (= 88.9)
100 − “88.9” (= 11.1)