4400 Higher June 2010 Paper 4 Q11
11 Simplify fully \(\dfrac{x}{6} + \dfrac{3x}{4}\)
(3)
| Scheme | Marks |
|---|---|
| both denoms = same multiple of 12 | M1 |
| \(\dfrac{2x + 9x}{12}\) or \(\dfrac{4x + 18x}{24}\) oe | M1 |
| \(\dfrac{11x}{12}\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: Any multiple of 12 acceptable
M1: \(\dfrac{2x}{12} + \dfrac{9x}{12}\) or \(\dfrac{4x}{24} + \dfrac{18x}{24}\) (intention to add correct fractions)
A1: cao