4400 Higher June 2008 Paper 3 Q21
21 The diagram shows part of the graph of \(y = \mathrm{f}(x)\).

(a) Calculate an estimate for the gradient of the curve at the point where \(x = 3\) (3)
(b) Find an estimate for the solution of the equation \(\mathrm{f}(x) = 0\) (1)
The equation \(\mathrm{f}(x) = mx + c\) where \(m\) and \(c\) are numbers, has three solutions.
Two of the solutions are \(x = -1\) and \(x = 1\)
(c)
(i) Find the value of \(c\).
(ii) Find the third solution of the equation \(\mathrm{f}(x) = mx + c\).
(4)| Scheme | Marks |
|---|---|
| tan drawn at (3, 6.5) | M1 |
| \(\dfrac{\text{vertical difference}}{\text{horizontal difference}}\) | M1 |
| 2.5 − 6.5 inc | A1 |
| (3) |
Notes
M1: tan or tan produced passes between points (2, \(0 \leqslant y \leqslant 4\)) and (4, \(9 \leqslant y \leqslant 12\))
M1: finds their \(\dfrac{\text{vertical difference}}{\text{horizontal difference}}\) for two points on tan
or finds their \(\dfrac{\text{vertical difference}}{\text{horizontal difference}}\) for two points on curve, where one of the points has an \(x\)-coordinate between 2.5 and 3 inc and the other point has an \(x\)-coordinate between 3 and 3.5 inc
A1: dep on both M marks
| Scheme | Marks |
|---|---|
| \(-1.7\) | B1 |
| (1) |
Notes
B1: Accept answer in range \(-1.7\) to \(-1.65\)
| Scheme | Marks |
|---|---|
| (i) line joining (\(-1\), 11) & (1, 13) | M1 |
| 12 | A1 |
| (ii) produces line to cut curve again | M1 |
| 4 | A1 |
| (4) | |
| (8 marks) |
Notes
A1: cao
A1: ft from line