4MA0 Higher January 2016 Paper 3R Q8
8 In 1981, the population of India was 683 million.
Between 1981 and 1991, the population of India increased by 163 million.
Give your answer correct to 3 significant figures. (2)
In 2001, the population of India was 1028 million.
Between 2001 and 2011, the population of India increased by 17.6%
Give your answer to the nearest million. (3)
In 2001, the population of India was 1028 million.
Between 1971 and 2001, the population of India increased by 87.6%
Give your answer correct to the nearest million. (3)
| Scheme | Marks |
|---|---|
| \(\dfrac{163\;(\text{million})}{683\;(\text{million})} \times 100\) | M1 |
| 23.9 | A1 |
| (2) |
Notes
A1: Accept 23.8 – 23.9
| Scheme | Marks |
|---|---|
| \(\dfrac{17.6}{100} \times 1028\) (million) or 180.(928) (million) | M1 |
| \(\dfrac{17.6}{100} \times 1028\) (million) + 1028 (million) | M1 |
| 1209 | A1 |
| (3) |
Notes
M1: M2 for 1028 (million) × 1.176 oe
A1: Accept 1208 – 1209
| Scheme | Marks |
|---|---|
| \(\dfrac{1028\;(\text{million})}{187.6} \times 100\) oe | M2 |
| 548 | A1 |
| (3) |
Notes
M2: M1 for \(\dfrac{1028\;(\text{million})}{187.6}\) or 5.47(9744136…) rounded or truncated to at least 3SF or 1.876 or (100 + 87.6)(%) or 187.6(%) or 187.6% = 1028 (million) or 1.876\(x\) = 1028 (million) oe or \(\dfrac{x}{1028\;(\text{million})} = \dfrac{187.6}{100}\) oe
A1: awrt 548