4MA0 Higher January 2016 Paper 3R Q18
18 There are 100 tiles in a bag.
Each tile is marked with a number.
The table shows information about the tiles.
| Number on tile | Frequency |
|---|---|
| 0 | 2 |
| 1 | 68 |
| 2 | 7 |
| 3 | 13 |
| 4 | 10 |
Carmen takes at random a tile from the bag.
She records the number on the tile and then replaces the tile in the bag.
Pablo takes at random a tile from the bag.
(a) Work out the probability that Carmen takes a tile with the number 0 or the number 1 and Pablo takes a tile with a number greater than 1 (2)
All 100 tiles are in the bag.
Juan takes at random a tile from the bag without replacing it.
He then takes a second tile from the bag.
(b)
(i) Work out the probability that the number on each tile is 4
(ii) Work out the probability that the total of the numbers on the two tiles is 2
(5)| Scheme | Marks |
|---|---|
| \(\dfrac{70}{100} \times \dfrac{30}{100}\) oe | M1 |
| \(\dfrac{21}{100}\) oe | A1 |
| (2) |
Notes
A1: eg \(\dfrac{2100}{10000}\) or 0.21
(i)
| Scheme | Marks |
|---|---|
| \(\dfrac{10}{100} \times \dfrac{9}{99}\) oe | M1 |
| \(\dfrac{1}{110}\) | A1 |
Notes
A1: oe eg \(\dfrac{90}{9900}\) or \(0.0\dot{0}\dot{9}\)
(ii)
| Scheme | Marks |
|---|---|
| \(\dfrac{2}{100} \times \dfrac{7}{99}\) or \(\dfrac{7}{100} \times \dfrac{2}{99}\) or \(\dfrac{14}{9900}\) or \(\dfrac{68}{100} \times \dfrac{67}{99}\) or \(\dfrac{4556}{9900}\) oe | M1 |
| \(\dfrac{2}{100} \times \dfrac{7}{99} + \dfrac{7}{100} \times \dfrac{2}{99} + \dfrac{68}{100} \times \dfrac{67}{99}\) oe | M1 |
| \(\dfrac{382}{825}\) | A1 |
| (5) |
Notes
M1: Implies first M1
A1: oe Eg \(\dfrac{4584}{9900}\) or \(0.46\dot{3}\dot{0}\)
Accept 0.463(0303…) rounded or truncated to at least 3 dp
With replacement method
| Scheme | Marks |
|---|---|
| \(\dfrac{2}{100} \times \dfrac{7}{100}\) or \(\dfrac{14}{10000}\) or \(\dfrac{68}{100} \times \dfrac{68}{100}\) or \(\dfrac{4624}{10000}\) oe | M1 |
| \(\dfrac{2}{100} \times \dfrac{7}{100} + \dfrac{7}{100} \times \dfrac{2}{100} + \dfrac{68}{100} \times \dfrac{68}{100}\) or \(\dfrac{1163}{2500}\) or 0.4652 oe | M1 |
Notes
M1: Implies first M1