4MA0 Higher January 2016 Paper 3 Q5
5 Kim asked 40 people how many text messages they each sent on Monday.
The table shows her results.
| Number of text messages sent | Frequency |
|---|---|
| 0 to 4 | 6 |
| 5 to 9 | 3 |
| 10 to 14 | 5 |
| 15 to 19 | 12 |
| 20 to 24 | 14 |
(a) Write down the modal class. (1)
(b) Calculate an estimate for the mean number of text messages sent. (4)
(c) What percentage of these 40 people sent 20 or more text messages? (2)
| Scheme | Marks |
|---|---|
| 20 to 24 oe | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| 2×6 + 7×3 + 12×5 + 17×12 + 22×14 or 12 + 21 + 60 + 204 + 308 or 605 | M2 |
"605" ÷ 40 or \(\dfrac{2 \times 6 + 7 \times 3 + 12 \times 5 + 17 \times 12 + 22 \times 14}{6 + 3 + 5 + 12 + 14}\) | M1 |
| 15.125 | A1 |
| (4) |
Notes
M2: freq × all correct midpoint values stated (or evaluated) with intention to add (condone any two errors in midpoints or frequencies)
If not M2 then award M1 for all products \(t \times f\) (and \(t\) is consistently within the interval, including end values) and intention to add (condone any two errors in their midpoints or frequencies)
M1: dep on at least M1
A1: accept 15 or 15.1 or 15.13 from correct working with no errors
(15 without working gains M0 A0)
NB. Accept 15.1625 (using 2.25 as mi-interval in first class)
| Scheme | Marks |
|---|---|
| 14 ÷ 40 × 100 oe | M1 |
| 35 | A1 |
| (2) |
Notes
M1: award M1 for 26 ÷ 40 × 100 or 65%