4MA0 Higher January 2014 Paper 4R Q2
2 Here are Ryan’s scores in nine French tests.
4 6 4 7 8 \(a\) 6 7 7
The mean of Ryan’s nine scores is 6
Work out the value of \(a\).
(3)
| Scheme | Marks |
|---|---|
| 4 + 6 + 4 + 7 + 8 + 6 +7 + 7 (= 49) or 9 × 6 (=54) | M1 |
| \(\dfrac{\text{“}49 + a\text{”}}{9} = 6\) oe or “54” – “49” | M1 |
| 5 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: M1 for 4 + 6 + 4 + 7 + 8 + \(a\) + 6 +7 + 7 = 49 + \(a\)
M1: dep