4MA0 Higher January 2013 Paper 4 Q10
10 Solve \(3x + 16 = 1 - 2x\)
Show clear algebraic working.
(3)
| Scheme | Marks |
|---|---|
| \(5x = -15\) or \(5x = 1 - 16\) or \(3x + 2x = -15\) or \(5x + 15 = 0\) | M2 |
| −3 | A1 |
| (3) |
Notes
M2: for correct rearrangement with \(x\) terms on one side and numbers on the other AND correct collection of terms on at least one side
M2 also for \(-5x = 15\), \(-5x = 16 - 1\) or \(-2x - 3x = 15\)
M1 for correct rearrangement with \(x\) terms on one side and numbers on the other eg \(3x + 2x = 1 - 16\) or \(16 - 1 = -2x - 3x\)
or correct collection and simplification of either numbers or \(x\) terms eg \(5x + 16 = 1\) or \(5x = a\) or \(5x - a = 0\) or \(nx = -15\) \((n \ne 5)\)
A1: Award 3 marks if M1 scored and answer correct.