4MA0 Foundation June 2017 Paper 2R Q24
24 Show that \(3\dfrac{1}{5} \div 2\dfrac{2}{3} = 1\dfrac{1}{5}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{16}{5}\) and \(\dfrac{8}{3}\) | M1 |
\(\dfrac{16}{5} \times \dfrac{3}{8}\) or \(\dfrac{48}{15} \div \dfrac{40}{15}\) | M1 |
| A fully correct method shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: For at least one correct improper fraction
M1: Dep
For first fraction unchanged, changing ÷ to × and inverting the 2nd fraction or
Converting each fraction with a common denominator of 15 (or multiple of 15) with ÷ sign
A1: \(\dfrac{48}{40}\) from correct working