4MA0 Foundation June 2014 Paper 2R Q20
20 Kim bought 12 boxes of drinks.
He paid $15 for each box.
There were 12 drinks in each box.
Kim sold \(\dfrac{3}{4}\) of the drinks for $1.50 each.
He sold all of the other drinks at a reduced price.
He made an overall profit of 15%.
Work out how much Kim sold each reduced price drink for.
(5)
| Scheme | Marks |
|---|---|
| Working with all 12 boxes 12 × 15 (=180) or 12 × 12 (=144) | M1 |
| \(12 \times 12 \times \dfrac{3}{4} \times 1.5\) oe (=162) | M1 |
| 12 × 15 × 1.15 oe (=207) or 180 × 0.15 oe (=27) | M1 |
| \(\dfrac{\text{“}207\text{”} - \text{“}162\text{”}}{36}\) or \(\dfrac{45}{36}\) or \(\dfrac{\text{“}27\text{”} + (\text{“}180\text{”} - \text{“}162\text{”})}{36}\) | M1 |
| 1.25 | A1 |
| (5) | |
| (Total 5 marks) |
Notes
M1: for correct total cost or correct total number of drinks (either may appear as part of another calculation)
M1: for revenue from all full price drinks sold
M1: for total revenue or total profit
M1: dep on M3
A1: cao
Alternative – working with one box
| Scheme | Marks |
|---|---|
| 15 ÷ 12 (=1.25) or \(12 \times \dfrac{3}{4}\) (= 9) | M1 |
| \(12 \times \dfrac{3}{4} \times 1.5\) oe (= 13.5) | M1 |
| 15 × 1.15 (=17.25) | M1 |
| \(\dfrac{\text{“}17.25\text{”} - \text{“}13.5\text{”}}{3}\) or \(\dfrac{3.75}{3}\) | M1 |
| 1.25 | A1 |
Notes
M1: for price of 1 drink or number of full price drinks
M1: for revenue from all full price drinks sold
M1: for total revenue from one box
M1: dep on M3
A1: cao