4MA0 Foundation January 2016 Paper 1 Q15
15 Kim asked 40 people how many text messages they each sent on Monday.
The table shows her results.
| Number of text messages sent | Frequency |
|---|---|
| 0 to 4 | 6 |
| 5 to 9 | 3 |
| 10 to 14 | 5 |
| 15 to 19 | 12 |
| 20 to 24 | 14 |
Kim is going to draw a pie chart for this information.
| Scheme | Marks |
|---|---|
| 6 ÷ 40 × 360 oe | M1 |
| 54 | A1 |
| (2) |
| Scheme | Marks |
|---|---|
| 20 to 24 oe | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| 2×6 + 7×3 + 12×5 + 17×12 + 22×14 or 12 + 21 + 60 + 204 + 308 or 605 | M2 |
“605” ÷ 40 or \(\dfrac{2\times6 + 7\times3 + 12\times5 + 17\times12 + 22\times14}{6 + 3 + 5 + 12 + 14}\) | M1 |
| 15.125 | A1 |
| (4) |
Notes
M2: freq × all correct midpoint values stated (or evaluated) with intention to add (condone any two errors in midpoints or frequencies)
If not M2 then award M1 for all products t × f (and t is consistently within the interval, including end values) and intention to add (condone any two errors in their midpoints or frequencies)
M1: dep on at least M1
A1: accept 15 or 15.1 or 15.13 from correct working with no errors
(15 without working gains M0 A0)
NB. Accept 15.1625 (using 2.25 as mi-interval in first class)
| Scheme | Marks |
|---|---|
| 14 ÷ 40 × 100 oe | M1 |
| 35 | A1 |
| (2) |
Notes
M1: award M1 for 26 ÷ 40 × 100 or 65%