4MA0 Foundation January 2015 Paper 2 Q13
13
(a) Work out \(\dfrac{5}{9}\) of 72 kg. (2)
(b) Show that \(\;\dfrac{1}{3} + \dfrac{4}{15} = \dfrac{3}{5}\) (2)
| Scheme | Marks |
|---|---|
72 ÷ 9 or 8 or \(\dfrac{5}{9} \times 72\) or 5 × 72 or 360 or 0.555(5…) × 72 oe | M1 |
| 8 × 5 or 360 ÷ 9 Answer: 40 | A1 |
| (2) |
| Scheme | Marks |
|---|---|
| \(\dfrac{5}{15} + \dfrac{4}{15}\) or \(\dfrac{5 + 4}{15}\) | M1 |
| \(\dfrac{9}{15}\) | A1 |
| (2) | |
| (4 marks) |
Notes
M1: for 2 fractions equivalent to \(\dfrac{1}{3}\) and \(\dfrac{4}{15}\) with a common denominator
eg. \(\dfrac{15}{45} + \dfrac{12}{45}\) or \(\dfrac{15 + 12}{45}\)
A1: dep on M1 for fraction equivalent to \(\dfrac{9}{15}\) (but not \(\dfrac{3}{5}\)) produced directly from M1