D2 June 2014 (R) Q7
7. Susie has hired a team of four workers who can make three types of toy. The total number of toys the team can produce will depend on which toys they make, and on how many workers are assigned to make each type of toy.
The table shows how many of each toy would be made if different numbers of workers were assigned to make them. Each worker is to be assigned to make just one type of toy and all four workers are to be assigned. Susie wishes to maximise the total number of toys produced.
| Number of workers | ||||||
|---|---|---|---|---|---|---|
| 0 | 1 | 2 | 3 | 4 | ||
| TOYS | Bicycle | 0 | 80 | 170 | 260 | 350 |
| Dolls House | 0 | 95 | 165 | 245 | 335 | |
| Train Set | 0 | 100 | 180 | 260 | 340 | |
E.g.
| Stage | State | Action | Dest | Value | Marks |
|---|---|---|---|---|---|
| Bicycle | 4 | 4 | 0 | 350 | 1M1 1A1 (2) |
| 3 | 3 | 0 | 260 | ||
| 2 | 2 | 0 | 170 | ||
| 1 | 1 | 0 | 80 | ||
| (0 | 0 | 0 | 0) | ||
| Dolls | 4 | 0 | 4 | 0 + 350 = 350 | |
| house | 1 | 3 | 95 + 260 = 355* | 2M1 2A1 3A1 (3) | |
| 2 | 2 | 165 + 170 = 335 | States 4 + 3 | ||
| 3 | 1 | 245 + 80 = 325 | |||
| 4 | 0 | 335 + 0 = 335 | |||
| 3 | 0 | 3 | 0 + 260 = 260 | ||
| 1 | 2 | 95 + 170 = 265* | |||
| 2 | 1 | 165 + 80 = 245 | |||
| 3 | 0 | 245 + 0 = 245 | |||
| 2 | 0 | 2 | 0 + 170 = 170 | 3M1 4A1 5A1 (3) | |
| 1 | 1 | 95 + 80 = 175* | |||
| 2 | 0 | 165 + 0 = 165 | States 2 + 1 | ||
| 1 | 0 | 1 | 0 + 80 = 80 | ||
| 1 | 0 | 95 + 0 = 95* | |||
| (0 | 0 | 0 | 0 + 0 = 0) | ||
| Train | 4 | 0 | 4 | 0 + 355 = 355 | |
| set | 1 | 3 | 100 + 265 = 365* | 4M1 6A1ft 7A1 (3) | |
| 2 | 2 | 180 + 175 = 355 | |||
| 3 | 1 | 260 + 95 = 355 | |||
| 4 | 0 | 340 + 0 = 340 |
| Scheme | Marks | ||||||||
|---|---|---|---|---|---|---|---|---|---|
| 1B1 | ||||||||
| (1) |
Notes
- ALL M marks - Must bring earlier optimal results into calculations. Ignore extra rows. Must have right ‘ingredients’ (– number of workers) at least once per stage.
- Penalise inconsistency/errors with the state/destination columns with the first two A marks earned only.
- Penalise empty/errors in stage column with first A mark earned only.
a1M1: First stage (Bicycle) completed – bod something in each cell. Must have columns for stage, state, value and one of either action or destination.
a1A1: CAO condone missing * here. Condone missing zero row.
a2M1: Second stage (Dolls house) completed for at least states 4 and 3. Bod something in each cell.
a2A1: Any one of these states correct. No missing rows. (Penalise * errors only once in the question).
a3A1: CAO both states 4 and 3 correct. No missing rows. (Penalise * errors only once in the question).
a3M1: Second stage (Dolls house) fully completed, condone missing zero row. Bod something in each cell.
a4A1: States 2 and 1 correct. No missing rows. (Penalise * errors only once in the question).
a5A1: CAO for stage 2. No missing rows. (Penalise * errors only once in the question).
a4M1: Third stage (Train set) completed. Bod something in each cell.
a6A1ft: Any three rows of third stage correct. Ft on * values only. No missing rows. (Penalise * errors only once in the question).
a7A1: CAO for the third stage. No missing rows. (Penalise * errors only once in the question).
a1B1: CAO. Must have attempted algorithm, getting all previous M marks.
| Scheme | Marks |
|---|---|
| Total number of toys is 365. | 1B1 |
| (1) | |
| 13 marks |
Notes
b1B1: CAO. Must have attempted algorithm, getting all M marks in (a).