Higher June 2025 Paper 2 Q7
7 Tim buys a bracelet for 4000 Swiss francs.
The value of the bracelet increases by 7% each year.
Work out the value of the bracelet at the end of 3 years.
Give your answer correct to the nearest Swiss franc.
(3)
| Scheme | Marks |
|---|---|
| 0.07 × 4000 (= 280) or 1.07 × 4000 ( = 4280) | M1 |
| 4000 + “280” (= 4280) oe and 0.07 × “4280” ( = 299.6) and “4280” + “299.6” (= 4579.6) and 0.07 × “4579.6” (= 320.572) or “280” + “299.6” + “320.572” (= 900(.172)) | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 4900 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for finding 7% of 4000 or 107% of 4000
A1: allow answers in the range 4900 – 4901
If no other mark awarded, SCB1 for
4000 × 0.07 × 3 (= 840) or
4000 × 0.21 (= 840) or
4000 + 4000 × 0.07 × 3 (= 4840) or
4000 × 1.21 (= 4840) or
0.93 × 4000 (= 3720) or
0.79 × 4000 (= 3160) or
\(0.93^3 \times 4000\) (= 3217…) or
\(4000 \times 1.07^2\) (= 4579…)
M2 for \(1.07^3 \times 4000\) or \(1.07^4 \times 4000\) ( = 5243….)