Higher June 2024 Paper 2 Q4
4 Show that \(\quad 2\dfrac{4}{7} \times 3\dfrac{1}{9} = 8\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{18}{7}, \dfrac{28}{9}\) | M1 |
\(\dfrac{\cancel{18}^{\,2}}{\cancel{7}_{\,1}} \times \dfrac{\cancel{28}^{\,4}}{\cancel{9}_{\,1}}\) or \(\dfrac{18}{7} \times \dfrac{28}{9} = \dfrac{504}{63}\) oe eg \(\dfrac{\cancel{18}^{\,2}}{7} \times \dfrac{28}{\cancel{9}_{\,1}} = \dfrac{56}{7}\) or \(\left(\dfrac{18}{7} \times \dfrac{28}{9} =\right) \dfrac{162}{63} \times \dfrac{196}{63} = \dfrac{31752}{3969}\) oe | M1dep |
eg \(\dfrac{\cancel{18}^{\,2}}{\cancel{7}_{\,1}} \times \dfrac{\cancel{28}^{\,4}}{\cancel{9}_{\,1}} = 8\) or \(\dfrac{\cancel{18}^{\,2}}{\cancel{7}_{\,1}} \times \dfrac{\cancel{28}^{\,4}}{\cancel{9}_{\,1}} = 2 \times 4 = 8\) eg \(\dfrac{18}{7} \times \dfrac{28}{9} = \dfrac{504}{63} = 8\) oe or eg \(\left(\dfrac{18}{7} \times \dfrac{28}{9} =\right) \dfrac{162}{63} \times \dfrac{196}{63} = \dfrac{31752}{3969}\left(= \dfrac{8}{1}\right) = 8\) working required Answer: Shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for correct improper fractions
M1dep: for cancelling fractions fully
or
cancelling fractions partially and clear intention to multiply (allow arithmetic error in multiplication)
or
not cancelling and clear intention to multiply (allow arithmetic error in multiplication)
A1: Dep on M2 for a correct answer of 8 from fully correct working
Candidates may show \(8 = \dfrac{8}{1}\) (maybe under the given 8) and then they need only show the given fraction comes to \(\dfrac{8}{1}\)