Higher June 2022 Paper 1R Q3
3 Here are five cards.
Each card has a number written on it.
| 15 | 7 | –2 | 23 | \(x\) |
The mean of the five numbers is 12
Work out the value of \(x\)
(3)
| Scheme | Marks |
|---|---|
5 × 12 (= 60) or \(\dfrac{15 + 7 - 2 + 23 + x}{5} = 12\) oe or \(\dfrac{x + \text{``}{43}\text{''}}{5} = 12\) | M1 |
| \(x + 15 + 7 - 2 + 23 = \text{``}{60}\text{''}\) or \(x + \text{``}{43}\text{''} = \text{``}{60}\text{''}\) or “60” – (15 + 7 – 2 + 23) | M1 |
| 17 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for a method to find the total of the 5 numbers or setting up an equation in \(x\)
“43” comes from 15 + 7 – 2 + 23
M1: for forming an equation with their 60 or for a complete calculation to find the value of \(x\)
“43” comes from 15 + 7 – 2 + 23