Higher January 2020 Paper 1R Q2
2 Show that \(\;3\dfrac{1}{5} \times 2\dfrac{5}{8} = 8\dfrac{2}{5}\)
(3)
| Scheme | Marks |
|---|---|
| e.g. \(\dfrac{16}{5}\) and \(\dfrac{21}{8}\) oe | M1 |
| e.g. \(\dfrac{\cancel{16}^{\,2}}{5} \times \dfrac{21}{\cancel{8}_{\,1}}\) OR \(\dfrac{336}{40}\) oe | M1 |
e.g. \(\dfrac{16}{5} \times \dfrac{21}{8} = \dfrac{336}{40} = \dfrac{42}{5} = 8\dfrac{2}{5}\) or \(\dfrac{16}{5} \times \dfrac{21}{8} = \dfrac{336}{40} = 8\dfrac{16}{40} = 8\dfrac{2}{5}\) or \(\dfrac{\cancel{16}^{\,2}}{5} \times \dfrac{21}{\cancel{8}_{\,1}} = \dfrac{42}{5} = 8\dfrac{2}{5}\) or candidate clearly shows that in the question, the result of \(8\dfrac{2}{5} = \dfrac{42}{5}\) and that their answer becomes \(\dfrac{42}{5}\) Working required Answer: shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: both fractions expressed as improper fractions
M1: correct cancelling or multiplication of numerators and denominators without cancelling
A1: Dep on M2 for conclusion to \(8\dfrac{2}{5}\) from correct working – either sight of the result of the multiplication e.g. \(\dfrac{336}{40}\) must be seen or correct cancelling prior to the multiplication to \(\dfrac{42}{5}\)
NB: use of decimals scores no marks