Higher January 2019 Paper 1R Q1
1 Show that \(1\dfrac{2}{3} + 2\dfrac{3}{4} = 4\dfrac{5}{12}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{5}{3} + \dfrac{11}{4}\) | M1 |
| \(\dfrac{20}{12} + \dfrac{33}{12}\) | M1 |
\(\dfrac{53}{12} = 4\dfrac{5}{12}\) Answer: Shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: converts to improper fractions
M1: converts to fractions with the same common denominator
A1: Dep on M2
| Scheme | Marks |
|---|---|
| \(\dfrac{2}{3} + \dfrac{3}{4} = \dfrac{8}{12} + \dfrac{9}{12}\) | M1 |
| \(\dfrac{17}{12} = 1\dfrac{5}{12}\) | M1 |
\(1\dfrac{5}{12} + 1 + 2 = 4\dfrac{5}{12}\) Answer: Shown | A1 |
Notes
M1: correct method to add proper fractions
A1: Dep on M2