Foundation November 2024 Paper 2 Q17
17 Show that \(1\dfrac{5}{7} \times 2\dfrac{3}{16} = 3\dfrac{3}{4}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{12}{7}\;(\times)\;\dfrac{35}{16}\) | M1 |
\(\dfrac{12}{7} \times \dfrac{35}{16} = \dfrac{420}{112}\) oe eg \(\dfrac{192}{112} \times \dfrac{245}{112} = \dfrac{47040}{12544}\) or \(\dfrac{\cancel{12}^{\,3}}{\cancel{7}_{\,1}} \times \dfrac{\cancel{35}^{\,5}}{\cancel{16}_{\,4}}\) oe or eg \(\dfrac{12}{\cancel{7}_{\,1}} \times \dfrac{\cancel{35}^{\,5}}{16} = \dfrac{60}{16}\) oe | M1 |
\(\dfrac{12}{7} \times \dfrac{35}{16} = \dfrac{420}{112} = \dfrac{15}{4} = 3\dfrac{3}{4}\) oe or \(\dfrac{12}{7} \times \dfrac{35}{16} = \dfrac{420}{112} = 3\dfrac{84}{112} = 3\dfrac{3}{4}\) oe \(\dfrac{\cancel{12}^{\,3}}{\cancel{7}_{\,1}} \times \dfrac{\cancel{35}^{\,5}}{\cancel{16}_{\,4}} = \dfrac{15}{4} = 3\dfrac{3}{4}\) oe Working required Answer: shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for both fractions written as improper fractions
M1: for multiplying the numerators and denominators
or
cancelling the fractions fully
or
partial cancelling and multiplying numerators and denominators
A1: completion to given result. dep on M2
If a student shows clearly in their working that \(3\dfrac{3}{4} = \dfrac{15}{4}\) they only need to show that the LHS comes to \(\dfrac{15}{4}\)