Foundation November 2020 Paper 2 Q15
15 Show that \(\;\dfrac{2}{5} \div \dfrac{11}{20} = \dfrac{8}{11}\)
(2)
| Scheme | Marks |
|---|---|
| \(\dfrac{2}{5} \times \dfrac{20}{11}\) or eg \(\dfrac{8}{20} \div \dfrac{11}{20}\) | M1 |
Working required \(\dfrac{2}{5} \times \dfrac{20}{11} = \dfrac{40}{55} = \dfrac{8}{11}\) or \(\dfrac{2}{\cancel{5}_{\,1}} \times \dfrac{\cancel{20}^{\,4}}{11} = \dfrac{8}{11}\) or \(\dfrac{8}{20} \div \dfrac{11}{20} = \dfrac{8}{11}\) Answer: Clearly shown | A1 |
| (2) | |
| (2 marks) |
Notes
M1: For inverting \(\dfrac{11}{20}\) and a clear intention to multiply or for writing both fractions correctly over the same common denominator
A1: dep on M1
continued to clearly show given result