Foundation June 2024 Paper 2 Q24
24 Ishir plants 600 bulbs in a garden.
He plants tulip bulbs, crocus bulbs and daffodil bulbs so that
number of tulip bulbs : number of crocus bulbs : number of daffodil bulbs = 9 : 4 : 2
45% of the tulip bulbs are for yellow flowers.
\(\dfrac{5}{8}\) of the crocus bulbs are for yellow flowers.
All of the daffodil bulbs are for yellow flowers.
Work out the number of bulbs that are for yellow flowers.
(5)
| Scheme | Marks |
|---|---|
600 ÷ (9 + 4 + 2) (= 40) or tulip: 0.45 × 600 (= 270) or crocus: \(\dfrac{5}{8} \times 600\ (= 375)\) or Tulips: 0.45 × 9 (= 4.05) or \(0.45 \times \dfrac{9}{15}\left(= \dfrac{27}{100}\ (= 0.27)\right)\) oe | M1 |
Daffodils: “40” × 2 (= 80) or \(\dfrac{2}{15} \times 600 (= 80)\) (implies 1st M1) or Crocus: \(\dfrac{5}{8} \times 4\ (= 2.5)\) or \(\dfrac{5}{8} \times \dfrac{4}{15}\left(= \dfrac{1}{6}\ (= 0.1\dot{6})\right)\) oe | M1 |
Tulip: 0.45 × (9 × “40”)(=162) or \(0.45 \times 600 \times \dfrac{9}{15}\ (= 162)\) (implies 1st M1) or Total of parts 4.05 + 2.5 + 2 (= 8.55) or \(\dfrac{27}{100} + \dfrac{1}{6} + \dfrac{2}{15}\left(= \dfrac{57}{100}\right)\) oe (implies 1st and 2nd M marks) | M1 |
Crocus: \(\dfrac{5}{8} \times (4 \times \text{``}{40}\text{''})\ (= 100)\) or \(\dfrac{5}{8} \times 600 \times \dfrac{4}{15}\ (= 100)\) (implies 1st M1) or \(\dfrac{8.55}{9 + 4 + 2} \times 600\) oe or \(\dfrac{57}{100} \times 600\) oe (implies all previous M marks) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 342 | A1 |
| (5) | |
| (5 marks) |
Notes
M1: A correct method to find one share (360 or 160 or 80 seen implies this method mark)
or 45% of 600 or \(\dfrac{5}{8}\) of 600
or
the fraction of the share that is for tulips
M1: A correct method to find number of daffodils
or
the fraction of the share that is for crocus
M1: A correct method to find number of yellow tulips
or
the total of the parts that are yellow
M1: A correct method to find number of yellow crocuses
or
multiplying the total of the correct shares by 600