Foundation June 2024 Paper 1R Q19
19 Show that \(\quad 2\dfrac{1}{3} \div 5\dfrac{1}{4} = \dfrac{4}{9}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{7}{3}\) and \(\dfrac{21}{4}\) | M1 |
\(\dfrac{7}{3} \times \dfrac{4}{21}\) oe eg \(\dfrac{49}{21} \times \dfrac{4}{21}\) or \(\dfrac{28}{12} \div \dfrac{63}{12}\) oe | M1 |
eg \(\dfrac{7}{3} \times \dfrac{4}{21} = \dfrac{28}{63} = \dfrac{4}{9}\) oe eg \(\dfrac{49}{21} \times \dfrac{4}{21} = \dfrac{196}{441} = \dfrac{4}{9}\) or \(\dfrac{\cancel{7}^{\,1}}{3} \times \dfrac{4}{\cancel{21}^{\,3}} = \dfrac{4}{9}\) oe or \(\dfrac{28}{12} \div \dfrac{63}{12} = \dfrac{28}{63} = \dfrac{4}{9}\) Working required Answer: Correctly shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: may have \(\dfrac{4}{21}\) rather than \(\dfrac{21}{4}\)
M1: for intention to multiply correct improper fraction and inverted fraction or writing the 2 fractions over the same common denominator
A1: for correctly completing to reach the required answer
Ignore any decimals used as checking.