Foundation June 2023 Paper 1R Q15
15 Show that \(\dfrac{3}{5} + \dfrac{2}{7} = \dfrac{31}{35}\)
(2)
| Scheme | Marks |
|---|---|
| eg \(\dfrac{21}{35}\) and \(\dfrac{10}{35}\) or \(\dfrac{21n}{35n}\) and \(\dfrac{10n}{35n}\) | M1 |
\(\dfrac{21}{35} + \dfrac{10}{35} = \dfrac{31}{35}\) \(\dfrac{21n}{35n} + \dfrac{10n}{35n} = \dfrac{31n}{35n} = \dfrac{31}{35}\) Working required Answer: Shown | A1 |
| (2) | |
| (2 marks) |
Notes
M1: for finding a common denominator with at least one fraction correct
A1: dep on M1, for a complete correct method leading to \(\dfrac{31}{35}\)