Foundation June 2022 Paper 1R Q24
24 Jane bought a new car for \(\$\)18 000
The car depreciates in value by 15% each year.
Work out the value of the car at the end of 4 years.
Give your answer correct to the nearest \(\$\)
(3)
| Scheme | Marks |
|---|---|
| \(18\,000 \times 0.15\) (= 2700) oe or \(18\,000 \times 0.85\) (= 15 300) oe | M1 |
| eg \(18\,000 \times 0.85^4\) oe or “15300” × 0.85 × 0.85 × 0.85 oe or “15300” × 0.85 (= 13005) oe and “13005” × 0.85 (= 11054.25) oe and “11054.25” × 0.85 oe | M1 |
| 9396 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for finding 15% or 85% of 18 000
M2 for \(18\,000 \times 0.85^4\) oe
or \(18\,000 \times 0.85^5\) (= 7986.(69…)) oe
M1: (dep) for a complete method
A1: awrt 9396
If no marks awarded, award SCB1 for
\(18\,000 \times 0.85^2\) (= 13 005) oe
or \(18\,000 \times 0.85^3\) (= 11 054.(25)) oe
or 18 000 × 0.4 (= 7200) oe
or 18 000 × 1.15 (= 20700) oe
or \(18\,000 \times 1.15^4\) (= 31482.(1125)) oe