Foundation June 2021 Paper 2 Q25
25 Chengbo sold a house for 180 000 yuan.
The amount for which he sold the house is 24% more than the amount he paid for the house.
Give your answer correct to 3 significant figures. (3)
Zhi bought a house on 1st January 2017
When she bought the house, its value was 120 000 yuan.
The value of the house increased by 1.8% per year.
Give your answer correct to 3 significant figures. (3)
| Scheme | Marks |
|---|---|
| eg 100 + 24 (=124 [%]) or 1 + 0.24 (= 1.24) or \(\dfrac{180000}{124}\) (= 1451.6...) | M1 |
| eg 180 000 ÷ 1.24 180 000 ÷ 124 × 100 or 180 000 × 100 ÷ 124 oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 145 000 | A1 |
| (3) |
Notes
M1: for a complete method
A1: accept 145 000 − 145 200
(if a correct answer is seen in working and then rounded incorrectly, award full marks)
(if no marks awarded, SCB1 for 223 200 or 223 000)
NB: this question is one where students could misread the number of zeros (eg one too many or one too few) in the question, up to M2 could be awarded if a correct method is seen with this misread
| Scheme | Marks |
|---|---|
| for 0.018 × 120 000 oe or 2160 or 1.018 × 120 000 oe or 122 160 | M1 |
| 1.018 × “122 160” (= 124 358.88) oe and 1.018 × “124 358.88” (= 126 597.34) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 127 000 | A1 |
| (3) | |
| (6 marks) |
Notes
M1: For finding 1.8% or 101.8% of the value
OR M2 for \(120\,000 \times 1.018^3\) or \(120\,000 \times 1.018^4\) or 128 876.09
(M1 for \(120\,000 \times 1.018^2\) or 124 358.88)
M1: for completing the method
A1: or 126 597 – 126 600
(if a correct answer is seen in working and then rounded incorrectly, award full marks)
SC: if no other marks gained award M1 for 1.054 × 120 000 oe or 126 480 or 6 480
accept (1 + 0.018) as equivalent to 1.018 throughout
NB: this question is one where students could misread the number of zeros in 120 000 (eg one too many or one too few) in the question, up to M2 could be awarded if a correct method is seen with this misread