Foundation June 2021 Paper 1 Q23
23 The table shows the populations of five countries.
| Country | Population |
|---|---|
| China | \(1.4 \times 10^9\) |
| Germany | \(8.2 \times 10^7\) |
| Sweden | \(9.9 \times 10^6\) |
| Fiji | \(9.1 \times 10^5\) |
| Malta | \(4.3 \times 10^5\) |
(a) Work out the difference between the population of China and the population of Germany.
Give your answer in standard form. (2)
Give your answer in standard form. (2)
Given that
\(\text{population of Fiji} = \dfrac{1}{k} \times \text{population of Sweden}\)
(b) work out the value of \(k\).
Give your answer correct to the nearest whole number. (2)
Give your answer correct to the nearest whole number. (2)
| Scheme | Marks |
|---|---|
| \(1.4 \times 10^9 - 8.2 \times 10^7\) or \(1.4 \times 10^9 - 0.082 \times 10^9\) or \(140 \times 10^7 - 8.2 \times 10^7\ (= 131.8 \times 10^7)\) | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: \(1.318 \times 10^9\) | A1 |
| (2) |
Notes
M1: or for 1 318 000 000 oe but not in standard form eg \(1318 \times 10^6\) or \(1.318 \times 10^n\) where \(n \neq 9\)
A1: Allow \(1.3 \times 10^9\) or \(1.32 \times 10^9\)
| Scheme | Marks |
|---|---|
| \(\dfrac{9.9 \times 10^6}{9.1 \times 10^5}\) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 11 | A1 |
| (2) | |
| (4 marks) |
Notes
A1: allow 10.8 – 11 (inclusive)
SC: if M1 not scored, award B1 for an answer of \(\dfrac{1}{11}\) allow 10.8 – 11 for the denominator