Foundation June 2019 Paper 1R Q24

EdexcelFoundationCurrent spec3 marksRatio & Basic Proportion

24 3 years ago, the ratio of Tom’s age to Clemmie’s age was 2 : 7
Tom is now 15 years old and Clemmie is now \(x\) years old.

Find the value of \(x\).

(3)

Mark scheme

Scheme	Marks
15 – 3 : \(x\) – 3 = 2 : 7 or (15 – 3) ÷ 2 (= 6) or (\(n\) =) (15 – 3) ÷ \(\dfrac{2}{2 + 7}\) (= 54) where \(n\) is the total age 3 years ago	M1
\(\dfrac{x - 3}{15 - 3} = \dfrac{7}{2}\) oe or 7 × “6” (= 42) or “54” × \(\dfrac{7}{2 + 7}\) (= 42)	M1
45	A1
	(3)
	(3 marks)

M1: M2 for \(\dfrac{(15 - 3) \times 7}{2}\) (= 42)