Foundation June 2018 Paper 2 Q20
20 Show that \(3\dfrac{4}{7} - 1\dfrac{5}{8} = 1\dfrac{53}{56}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{25}{7}\) and \(\dfrac{13}{8}\) | M1 |
| eg \(\dfrac{200}{56} - \dfrac{91}{56}\) or \(\dfrac{8 \times 25}{56} - \dfrac{7 \times 13}{56}\) | M1 |
Working required \(\dfrac{109}{56} = 1\dfrac{53}{56}\) Or \(\dfrac{109}{56}\) with RHS shown as \(\dfrac{109}{56}\) Answer: correctly shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: correct improper fractions or two improper fractions with a common denominator, at least one correct
M1: two correct fractions with a common denominator
A1: dep on M2 with sight of the result of the subtraction eg \(\dfrac{109}{56}\) and \(1\dfrac{53}{56}\) but allow showing that \(1\dfrac{53}{56} = \dfrac{109}{56}\) on RHS in working
| Scheme | Marks |
|---|---|
| eg \((3)\dfrac{32}{56} - (1)\dfrac{35}{56}\) | M1 |
| \(-\dfrac{3}{56}\) | M1 |
| Working required Answer: correctly shown | A1 |
Notes
M1: two improper fractions with a common denominator, at least one correct
M1: correct subtraction of fractional parts
A1: dep on M2 with sight of the result of the subtraction eg \(\dfrac{109}{56}\) or \(2 - \dfrac{3}{56}\)
| Scheme | Marks |
|---|---|
| eg \(3\dfrac{32}{56} - 1\dfrac{35}{56}\) | M1 |
| eg \(2\dfrac{88}{56} - 1\dfrac{35}{56}\) | M1 |
| Working required Answer: correctly shown | A1 |
Notes
M1: two correct fractions with a common denominator, at least one correct
M1: complete correct method
A1: dep on M2