Foundation January 2023 Paper 2R Q11
11 Asif has 200 beads.
Asif gives \(\dfrac{1}{4}\) of the 200 beads to Bernadette.
Asif gives \(\dfrac{2}{5}\) of the 200 beads to Claudio.
Asif gives 43 beads to Derek.
What fraction of the 200 beads does Asif have left?
(4)
| Scheme | Marks |
|---|---|
| eg \(\dfrac{1}{4} \times 200\;(= 50)\) or \(\dfrac{2}{5} \times 200\;(= 80)\) OR \(\dfrac{43}{200}\) | M1 |
eg \(\dfrac{1}{4} \times 200\;(= 50)\) and \(\dfrac{2}{5} \times 200\;(= 80)\) OR \(\dfrac{43}{200} + \dfrac{1}{4} + \dfrac{2}{5}\left(= \dfrac{173}{200}\right)\) | M1 |
| eg 200 – “50” – “80” – 43 (= 27) OR \(1 - \text{“}\dfrac{173}{200}\text{”}\) | M1 |
Correct answer scores full marks (unless from obvious incorrect working) Answer: \(\dfrac{27}{200}\) | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for a method to find the beads for Bernadette or Claudio OR Derek’s beads as a fraction
M1: for a method to find the beads for Bernadette and Claudio
OR method to find the fraction of the 200 beads given away
M1: for a method to find the number of beads Asif has left
OR 1 – the fraction of the 200 beads given away
A1: cao