Higher June 2018 Paper 1 Q17
17 Simplify fully \(\dfrac{3x^2 - 8x - 3}{2x^2 - 6x}\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(\dfrac{3x + 1}{2x}\) | M1 | for \((3x + 1)(x - 3)\) or \(2x(x - 3)\) |
| A1 | for \((3x + 1)(x - 3)\) and \(2x(x - 3)\) | |
| A1 | \(\dfrac{3x + 1}{2x}\) oe |
Additional guidance
Accept \((2x + 0)\) for the first two marks but not for the final answer